A quantity x varies inversely as the square of y. Given that x = 4 when y = 3, the value of x when y

A quantity x varies inversely as the square of y. Given that x = 4 when y = 3, the value of x when y




Solution -

x=k/(y*y). From given data 4=k/(3*3) gives k=36
Thus x=36/(y*y)
When y=6, x=36/(6*6) means x=1 answer